You may need to use the appropriate appendix table or technology to answer this question.Given are five observations collected in a regression study on two variables.* 26 i3 20Y7 19 7 27 21Develop the 95% confidence and prediction intervals when x 10. (Round your answers to two decimal places)10.02420confidence intervalX to 2248prediction intervalx to 30.00Explain why these two intervals are different.The two intervals are different because there is more variability associated with predicting an individual value than there is with estimating a mean value.The two intervals are different because there is les variabity associated with predicting an individual value than there is with estimating a mean value.O The two intervals are different because you use a different oritical value when developing a confidence interval than when developing a prediction interval.O The two intervals are different because confidence intervais are used to predict values of Afor new observations corresponding to given values of x, and prediction intervals give an estimate ofthe mean value of y for a given value of .Need Help?eadiSubmit Answwor

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 21 wolf litters in Ontario, Canada, gave an average of x1 = 4.7 wolf pups per litter, with estimated sample standard deviation s1 = 1.0. Another random sample of 7 wolf litters in Finland gave an average of x2 = 2.8 wolf pups per litter, with sample standard deviation s2 = 1.4. (a) Find an 85% confidence interval for ?1 – ?2, the difference in population mean litter size between Ontario and Finland. (Round your answers to one decimal place.) lower limit upper limit (b) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 85% level of confidence, does it appear that the average litter size of wolf pups in Ontario is greater than the average litter size in Finland? Because the interval contains only positive numbers, we can say that the average litter size of wolf pups is greater in Ontario.Because the interval…
The regression equation attached has been fitted to 20 data points. The means of x1 and x2 are equal to 25 and 40 respectively. The sum of squared differences between observed and predicted values of y have been calculated to be SSE = 133.5, and the sum of squared differences between y and the mean of y is SST = 490.8. Determine the following: a. The multiple standard error of estimate. b. The approximate 95 percent confidence interval for the mean of y whenever x1 = 22 and x2 = 29. c. The approximate 95 percent prediction interval for an individual y value whenever x1 = 22 and x2 = 29. d. Calculate and interpret the coefficient of determination for this regression
The 98 percent confidence interval (−0.248,−0.134) was constructed to estimate the slope of a regression model for a bivariate data set with 20 values. Alice claims that a sample size of 25 will produce a narrower interval, all other things remaining the same. Desmond claims that a sample size of 15 will produce a narrower interval. Which statement is true about the claims made by Alice and Desmond?
An argument for the fact that males are often paid more than females is that they have more experience, because females take time out of the workforce. Calculate a 95% confidence interval for the average number of years employed of male employees and another one for the average number of years employed for females. Compare the intervals, and, based on these results what do you conclude overall about the difference in salaries between male and female employees? Given these data, using excel to solve this problem. Gender Yrs Employed Salary F 13.0 64991 F 12.7 63000 F 12.2 99351 F 12.1 47837 F 11.9 63682 F 11.5 65707 F 11.2 62514 F 10.8 60120 F 10.7 220450 F 10.5 51777 F 10.3 64816 F 10.2 66441 F 10.2 60724 F 10.2 59026 F 10.2 57859 F 10.1 53171 F 10.1 54132 F 10.0 70131 F 9.8 47961 F 9.8 74241 F 9.7 66593 F 9.6 46738 F 9.6 54828 F 9.4 250000 F 9.4 74226 F 9.4 64021 F 9.4 46335 F 9.4 55425 F 9.4 65714 F 9.4 57583 F 9.4…
A sample of 8 female college students consumes an average of 10 liters of alcohol per month, with a sample standard deviation of 3.9 liters. Monthly alcohol consumption is Normally distributed. What is the margin of error for a 99% Confidence Interval for the mean? (Leave your answer to two decimal places, ex: 18.12)
Please reply as soon as possible. Maxforce inc manufactures racquetball racquets by two manufacturing processes (A and B). Because the management of the company is interested in estimating the difference between the avarage time it takes to each process to produce a racquet, they select independent samples from each process. The results of the samples are shown below Process A Process B Sample size 32 35 sample mean (in min) 43 47 Population standard deviation. 8 8.5 1. Develop a confidence interval estimate for the difference between the avarage time of the two process. 2. Is there a conclusive evidence that one process takes longer than the other?Use both critical value and the p- value approach
You may need to use the appropriate appendix table or technology to answer this question. Given are five observations for two variables, x and y. (Round your answers to two decimal places.) xi 3 12 6 20 14 yi 60 35 55 15 15 #1) Estimate the standard deviation of ŷ*when x = 7. #2) Develop a 95% confidence interval for the expected value of y when x = 7. _____to ________ #2a) Estimate the standard deviation of an individual value of y when x = 7. #3)Develop a 95% prediction interval for y when x = 7. _____to_______
What price do farmers get for their seedless watermelon crops? In a recent month, a simple random sample of 32 farming regions gave a sample mean of $12.15 per 100 pounds of seedless watermelon. Assumer that σ=$1.57σ=$1.57 per 100 pounds.Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their seedless watermelon crop. (Round answers to two decimal places.)margin of error: $ per 100 poundslower limit: $ per 100 poundsupper limit: $ per 100 poundsWhat conditions were met for the above calculations to be valid? (Select all that apply.) σσ is known The price per 100 pound of seedless watermelon needs to be normally distributed large enough sample size n σσ is unknown The price per 100 pound of seedless watermelon needs to be uniformly distributed Find the sample size necessary for a 90% confidence level with an margin of error E=0.35E=0.35 for the mean price per 100 pounds of seedless watermelon. (Increase to the next…
You may need to use the appropriate appendix table or technology to answer this question. Given are five observations for two variables, x and y. (Round your answers to two decimal places.) xi 1 2 3 4 5 yi 4 8 4 11 13 (a) Use sŷ* = s 1 n + (x* − x)2 Σ(xi − x)2 to estimate the standard deviation of ŷ* when x = 5. (b) Use ŷ* ± t?/2sŷ* to develop a 95% confidence interval for the expected value of y when x = 5. to (c) Use spred = s 1 + 1 n + (x* − x)2 Σ(xi − x)2 to estimate the standard deviation of an individual value of y when x = 5. (d) Use ŷ* ± t?/2spred to develop a 95% prediction interval for y when x = 5. to
You may need to use the appropriate appendix table or technology to answer this question. Given are five observations for two variables, x and y. (Round your answers to two decimal places.) xi 1 2 3 4 5 yi 4 8 5 11 15 (a) Use sŷ* = s 1 n + (x* − x)2 Σ(xi − x)2 to estimate the standard deviation of ŷ* when x = 5. (b) Use ŷ* ± t?/2sŷ* to develop a 95% confidence interval for the expected value of y when x = 5. to (c) Use spred = s 1 + 1 n + (x* − x)2 Σ(xi − x)2 to estimate the standard deviation of an individual value of y when x = 5. (d) Use ŷ* ± t?/2spred to develop a 95% prediction interval for y when x = 5. to I need all the parts, I attached a picture of the whole question in case the one I copied above was not clear enough.
A researcher is investigating the relationship between the length, in centimeters, and weight, in grams, of pineapples. The researcher will select a random sample of 15 pineapples from grocery stores in a region and construct a 95 percent confidence interval for the slope of the population regression line, where length is the explanatory variable and weight is the response variable. When computing a confidence interval for the slope of the population regression line, which of the following is not a condition that must be checked? The true relationship between length and weight is linear. A The standard deviation for weight does not vary with length. B The values of weight are approximately normally distributed at each value of length. C The sum of the residuals is zero. D The observations are independent. E
A researcher was interested in the relationship between the number of texts sent in a day and the number of e-mails sent in a day by employees at a certain company. Using 15 data values, a 90 percent confidence interval for the slope of a regression model was found to be (2.31,3.47). The researcher claims that the interval would have been narrower with a different sample size if all other things remained the same. Which of the following sample sizes would make the researcher’s claim NOT true?

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