You obtained the sequence of the frog gene X you amplified in Question #16 through a process called automated sequencing. In automated sequencing, you are given a printout of the sense strand of your DNA.  The first thing you need to do is use the correct reading frame. Having done this, the next thing to do is to write out the mRNA sequence using this sense strand reading frame. The last thing to do is to translate the sequence.  a.The reading frame DNA sequence is: b.The mRNA sequence is: c.The polypeptide sequence is: A disease in frogs which causes their tongue to fall out of their mouths is killing the frog population in LA County. You obtain a dead frog and isolate its gene Xf. When you sequence this mutated gene, you find that the last ‘G’ at the end of the first line of this sequence has been deleted (i.e. the G at position 86). In order to determine how this mutation changes the resulting polypeptide, write the mutated polypeptide sequence in the space below. What kind of mutation was produced? d. The mutated polypeptide sequence is now:   e. This deletion mutation was a __________________________________ mutation

Comprehensive Medical Terminology
4th Edition
ISBN:9781133478850
Author:Jones
Publisher:Jones
Chapter21: Oncology (cancer Medicine)
Section: Chapter Questions
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 You obtained the sequence of the frog gene X you amplified in Question #16 through a process called automated sequencing. In automated sequencing, you are given a printout of the sense strand of your DNA. 

The first thing you need to do is use the correct reading frame.

Having done this, the next thing to do is to write out the mRNA sequence using this sense strand reading frame. The last thing to do is to translate the sequence. 

a.The reading frame DNA sequence is:

b.The mRNA sequence is:

c.The polypeptide sequence is:

A disease in frogs which causes their tongue to fall out of their mouths is killing the frog population in LA County. You obtain a dead frog and isolate its gene Xf. When you sequence this mutated gene, you find that the last ‘G’ at the end of the first line of this sequence has been deleted (i.e. the G at position 86). In order to determine how this mutation changes the resulting polypeptide, write the mutated polypeptide sequence in the space below. What kind of mutation was produced?

d. The mutated polypeptide sequence is now:

 

e. This deletion mutation was a __________________________________ mutation

 
File: gvt11b11.y1
Machine: Cochise-1414-017
Matric
Lane: 93
Primer: DT3730POP7{BDV3}.mob
Comment: 1778D3
Spacing: 15.06
Signal: C: 1728 A: 3254 G: 2538 T: 2619
Bases: 903
Gel name:
Gel start date: 3 Jan 2004
Gel start time: 4:123
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NNACTCA TCTGGTGGA TTC C TA TC CTG AC A AG TG ATGTG CAAA C TG G TAACTC TG AG GCAG A TAAC CA G GG CA AA AAG GTG TATAAG
130
90
TAAA ACA AAGCCTAACT TG GAAGA AAGAGAGA AAAAGT TCA GTT TTACAÇA TCTTTA TA TGAAGCAGA AG TCCGGA AA A TCA TT TA AAGAT
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TAT TCTAT TA ATGTCCTG T TA TAT T TG T CA TATTCA TA CAGT TG TCA CA GTA TATT TCA AAC CA A C TG TTTAAA A ACAAAC TG A AA TAAA
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AAATTTAAA TACCCT TA TG TA AA ATAG GCT TC CCTGGTG GCTCAG GG GTAAAAA ACTCGCCCG C CA ACGCAG GAGATGTAGAT TT GATC CC T
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GG GT TAG G A AGATCCC CTG GAGA AGGAAATGAA AAAC CACTCTAGTATTCT TGC CTG GG AA AT C CCATGGACAG AG GAGCGTG GAG G GC
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TACAGTCCATGGGAGTCGCAAA AGAGT TG GACATG ACTAAACAACAACATATAAAATAACCT TACTC CATAATGTCAAACT TATGTCACAC
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AAA ATGCAA AGT TCT TACATCTAT TA ACTTTTATGGT TA AATATA AC CTAATGCACTGTTT TATACAGCAACAACTACTTTIT TAIII TA AA
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TG GTGAAA AAT TAGTGA ACAGAGGGT CTCAGAGATGCTAAACTTATGACT TATAAT TAACAAGATGTTATAGTTCTAGACAT TTTTGATAT
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Transcribed Image Text:File: gvt11b11.y1 Machine: Cochise-1414-017 Matric Lane: 93 Primer: DT3730POP7{BDV3}.mob Comment: 1778D3 Spacing: 15.06 Signal: C: 1728 A: 3254 G: 2538 T: 2619 Bases: 903 Gel name: Gel start date: 3 Jan 2004 Gel start time: 4:123 10 20 30 40 50 60 70 80 NNACTCA TCTGGTGGA TTC C TA TC CTG AC A AG TG ATGTG CAAA C TG G TAACTC TG AG GCAG A TAAC CA G GG CA AA AAG GTG TATAAG 130 90 TAAA ACA AAGCCTAACT TG GAAGA AAGAGAGA AAAAGT TCA GTT TTACAÇA TCTTTA TA TGAAGCAGA AG TCCGGA AA A TCA TT TA AAGAT 100 110 120 140 150 160 170 180 190 200 210 220 230 240 250 260 TAT TCTAT TA ATGTCCTG T TA TAT T TG T CA TATTCA TA CAGT TG TCA CA GTA TATT TCA AAC CA A C TG TTTAAA A ACAAAC TG A AA TAAA 280 320 270 AAATTTAAA TACCCT TA TG TA AA ATAG GCT TC CCTGGTG GCTCAG GG GTAAAAA ACTCGCCCG C CA ACGCAG GAGATGTAGAT TT GATC CC T 290 300 310 330 340 350 360 GG GT TAG G A AGATCCC CTG GAGA AGGAAATGAA AAAC CACTCTAGTATTCT TGC CTG GG AA AT C CCATGGACAG AG GAGCGTG GAG G GC 370 380 390 400 410 420 430 440 450 460 470 480 490 500 510 520 530 TACAGTCCATGGGAGTCGCAAA AGAGT TG GACATG ACTAAACAACAACATATAAAATAACCT TACTC CATAATGTCAAACT TATGTCACAC 560 600 620 540 AAA ATGCAA AGT TCT TACATCTAT TA ACTTTTATGGT TA AATATA AC CTAATGCACTGTTT TATACAGCAACAACTACTTTIT TAIII TA AA 550 570 580 590 610 630 680 720 TG GTGAAA AAT TAGTGA ACAGAGGGT CTCAGAGATGCTAAACTTATGACT TATAAT TAACAAGATGTTATAGTTCTAGACAT TTTTGATAT 640 650 660 670 690 700 710
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