You will perform the protocol below for the calf intestinal alkaline phosphatase (CIP) provided. For each reaction, your final enzyme concentration should be 10 nM CIP. Note: Enzymes purchased are typically labelled with their “units of activity” (U), as this relates to how much enzyme is needed to catalyze a reaction. The 100 nM CIP provided has approximately 3 U/mL and was diluted 1 in 1,000 from a 500 U/mL purchased enzyme. 1) Create a table (similar to the one below) to help you determine and keep track of what to add to each of the cuvettes in which your reactions will be measured. The five different concentrations of PNPP should be: 25, 50, 100, 200, 300 μM. Each reaction will be in a final volume of 1 mL and contain 10 nM alkaline phosphatase. Concentrations of stock solutions: 1.0 mM PNPP, 100 nM calf intestinal phosphatase

Curren'S Math For Meds: Dosages & Sol
11th Edition
ISBN:9781305143531
Author:CURREN
Publisher:CURREN
Chapter10: Reconstitution Of Powdered Drugs
Section: Chapter Questions
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You will perform the protocol below for the calf intestinal alkaline phosphatase (CIP) provided. For each reaction, your final enzyme concentration should be 10 nM CIP.

Note: Enzymes purchased are typically labelled with their “units of activity” (U), as this relates to how much enzyme is needed to catalyze a reaction. The 100 nM CIP provided has approximately 3 U/mL and was diluted 1 in 1,000 from a 500 U/mL purchased enzyme.

1) Create a table (similar to the one below) to help you determine and keep track of what to add to each of the cuvettes in which your reactions will be measured. The five different concentrations of PNPP should be: 25, 50, 100, 200, 300 μM. Each reaction will be in a final volume of 1 mL and contain 10 nM alkaline phosphatase.

Concentrations of stock solutions: 1.0 mM PNPP, 100 nM calf intestinal phosphatase

Final [] of
PNPP (μM)
Vol H₂O
(μL)
Vol of 1.0 mM
PNPP (μL)
Vol of 2x
reaction buffer
(μL)
Final [] of
enzyme (nM)
Vol of enzyme
(μL)
Transcribed Image Text:Final [] of PNPP (μM) Vol H₂O (μL) Vol of 1.0 mM PNPP (μL) Vol of 2x reaction buffer (μL) Final [] of enzyme (nM) Vol of enzyme (μL)
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can you follow up on how to solve for the volume of water and 2x buffer in depth, then the volume of the enzyme? I don't understand how you got those numbers

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