Answered: You work as a test engineer for a…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter29: Direct Current (dc) Circuits

Section29.5: Resistors In Parallel

Problem 29.7CE

See similar textbooks

Related questions

Question

You work as a test engineer for a global manufacturer of electrical and mechanical components and systems.Your Line manager is responsable for delagating to you and your collegues the testing of theory,principles and hypotheses fromseveral worldwide company divisions .She has asked you to undertake a series of evaluations.

a) The power (P) dissapated in a resistor (R) which is subjected to a voltage (V) across its terminals is given by the well known formula;

P=V^2/R

use the dimension of P and V to determine the dimensions of (R)

Expert Solution

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Follow-up Questions

Read through expert solutions to related follow-up questions below.

Follow-up Question

Voltage on my table is V=[L^0.5 M^0.5 T^-1]

if i was to use this V how would the equation turn out

[mass]
[length]
[time]
[area]
[volume]
[density]
[velocity]
[acceleration]
[force]
[moment of force, torque]
[impulse]
[momentum]
[work]
[kinetic energy]
[power]
[electrical charge]
[current]
[electric potential energy]
[voltage]
[capacitance]
[inductance]
[electrical resistance]
M
L
T
[length x length]
[area x length]
[mass/volume]
[length/time]
[velocity/time]
[mass x acceleration]
MLT-2 x L
time]
[mass x velocity]
[force x distance]
[mass x (velocity)²]
[work/time]
[length x (force)05]
[electrical charge/time]
[charge2/distance]
[electric potential energy/charge]
[charge/voltage]
[voltage x time/current]
[voltage/current]
M
L
T
L²
L3
ML-3
LT-1
LT-²
MLT-²
ML²T-²
MLT¹
MLT-¹
ML²T-²
ML²T-²
ML²T-3
L1.5M0.5T-1
L¹.5M0.5T-2
L²MT²
L05M0ST
L
L-¹T²
L''T

Solution

by Bartleby Expert

SEE SOLUTION

Follow-up Question

i should have said where;

p=V^2/R

P=[ML^2 T^-3]

V=[L^0.5 M^0.5 T^-1]

solve for R

Solution

by Bartleby Expert

SEE SOLUTION

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions