You're designing a highway so that the maximum centripetal acceleration on a curve is no more than 1.3 m/s^2. What is the minimum curvature radius to accommodate a 108 km//h maximum speed? This is about r=V^2/a, right? I have to convert km to meters, then hours to min to seconds.  Say the final is (30m/s)^2 /1/3 m/s^2 =692.3 m Does two sig figs mean that 692 is changed to 690 m or something else to get two sig figs?  Please explain?  If the answer is 62.3 then two figs mean 62. If 63.5, then 64.  But 692?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
Section: Chapter Questions
Problem 31P: Figure P3.31 represents the total acceleration of a particle moving clockwise in a circle of radius...
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You're designing a highway so that the maximum centripetal acceleration on a curve is no more than 1.3 m/s^2.

What is the minimum curvature radius to accommodate a 108 km//h maximum speed?

This is about r=V^2/a, right?

I have to convert km to meters, then hours to min to seconds.  Say the final is (30m/s)^2 /1/3 m/s^2 =692.3 m

Does two sig figs mean that 692 is changed to 690 m or something else to get two sig figs?  Please explain?  If the answer is 62.3 then two figs mean 62. If 63.5, then 64.  But 692?

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