How would I find the z score and p value I have my work above The director of student services at Oxnard College is interested in whether women are less likely to attendorientation than men before they begin their coursework. A random sample of freshmen at Oxnard Collegewere asked what their gender is and whether they attended orientation. The results of the survey areshown below:+F3What can be concluded at the a= 0.01 level of significance?For this study, we should use z-test for the difference between two population proportionsa. The null and alternative hypotheses would be:F4Ho: p1p2v(please enter a decimal and notethat p1 and ul represent the proportion and mean for women and p2 and 2 represent the proportion andmean for men.)H₁: p1b. The test statistic zc. The p-value = 4940d. The p-value is vae. Based on this, we should fail to rejectf. Thus, the final conclusion is that ...$Data for Gender vs.OrientationAttendanceCYes 354No315F5Women Men363272%F6The results are statistically insignificant at a = 0.01, so there is statistically significantevidence to conclude that the population proportion of freshmen women at Oxnard Collegewho attend orientation is the same as the population proportion of freshmen men at OxnardCILMLI9p2= -0.015 x (please show your answer to 3 decimal places.)x (Please show your answer to 4 decimal places.)F7✓✓the null hypothesis.&QF8(Please enter a decimal)8*F909F10-0:-F110:+F12Prt 1) Ho = P₁ = P₂H₁ = P₁ P2x₁ = 354X2=315n₁=354+363 and n₂=315+ 272=717= 587P₁ = x₁niê-n₂=354717315587= x₁ + x21₁+h2(354 +315)(717+587)= 49372.63366Test StatisticZ =49372 +5366√ (5130) (1 487) (1717 + =587)..0429pc.51306691,304 9-1-2.487

Question

Accepted Answer

your sample proportions are wrong
From given data we have:
n1=354+315=669n2=363+272=635x1=354x2=363