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- Using Flowgorithm, create an application that reads two integers, determines whether the first is a multiple of the second and prints the result. [Hint:Prompt for the user to enter their name. Print out their name forwards, backwards, vertically-forwards and vertically-backwards. You will need to declare a String variable, use Scanner to get input of a String, call a String method to isolate one letter and create a loop that traverses the name forwards and backwards. Sample Output: Enter your name: Florene Florene enerolF F l o r e n e e n e r o l F HINTS: Scanner input = new Scanner(System.in); String myName = input.nextLine(); // input is a Scanner object int len = myName.length() // len is the number of characters System.out.println (myName.substring(len-1, len)); // prints last letter I need help with coding the name "Pooja" vertically-forwards and vertically-backwards in java. If you could show me what codes to type in, that would be great. Thank you!To take a screenshot, press ____ Group of answer choices Print Screen Insert Ctrl + P Ctrl + C
- C++ - Creating a menu (menuOption) - Need assistance in creating a menu that opens up an entirely new menu once the user inputs the appropriate value (range is 0 to 13). - The main photo shows how the initial menu should look like and each title has its own value assigned to it. Also, in the bottom of the photo is "Option : " and there, the user is suppose to input a value that will open up one of the menus. - So if the user inputs 3, then a completely new menu populates on the user's screen (please review photo number two). And in this new populated screen it is title "3. Drop Lowest Score." There is a line below the title and under that line the user is suppose to perform an action but I have yet to create code for that (hence is why I have "case #: Challenge#(); break;"). - But if the user inputs a value that is not within the range OR a letter, then below "Option : " (on the main menu) the program must state an error message such as the following: Option : 14 ERROR - Invalid…Please don't copy the answer Graph the following functions using the console . Use SCILABDraw the following FlowChart in Raptor and upload the Raptor file into the assignment folder. Draw a table variable (for a, b, M) on a paper assuming the user insert M=7 when it is asked by raptor, and upload it to the assignment folder. Which of the following are final values for n and sum, if the user inserts M=7 when it is asked by Raptor? Capital and Lowercase M is similar in this example (m=M) On paper, write what is the purpose of this algorithm. a = 1, b=2, m=7 a = 2, b=4, m=7 a = 8, b=8, m=7 a = 16, b=16, m=7 a = 16, b=16, m=8
- **Program must match the photo** This lab is to to add another option for the user to print warnings of any inventory running low. More specifically:- Add another option to the menu, called W for Warning- Look at all items, in all locations. If an item has less than 10 left, print out on one line the item name,location, and quantity.A photo of the example run is attached Contents of Inventory.txt Red delicious apples1.00 25 6 8 10Assorted bouquets4.00 50 10 10 0Camembert cheese2.00 25 10 12 4END Program that is being added to: #include <iostream>#include <fstream>#include <vector>using namespace std; struct Record {string name;double cost;int markup;int count[3];}; const string places[3] = {"counter", "shelf", "warehouse"}; bool read_file(vector <Record> &v);void placement (vector <Record> &v); int main(){vector <Record> invent;char choice; if (read_file(invent) == false) {return 1;}cout << "You have " << invent.size() <<…Change your code below to create a pattern using nested loops. Your initial needs to appear at least eight times in the pattern and pattern doesn't matter. import turtle # Setting background color screen = turtle.Screen()screen.bgcolor("skyblue") #drawing letter 'M' in color dark blue turtle.penup()turtle.pensize(9) turtle.color("dark blue")turtle.goto(-300,200)turtle.pendown()turtle.right(90)turtle.forward(300)turtle.backward(300)turtle.left(45)turtle.forward(200)turtle.left(90)turtle.forward(200)turtle.right(135)turtle.forward(300)turtle.backward(300) # adding space between M and P turtle.left(90)turtle.penup()turtle.forward(100)turtle.pendown() #drawing letter 'P' in color green turtle.pensize(8)turtle.color("green")turtle.right(90)turtle.forward(300)turtle.backward(150)turtle.left(90)turtle.circle(75,extent=180) turtle.doneWe can view a list of variables store in the Variable PSDrive with this cmdlet. Select the best answer: Group of answer choices Get-ChildItem Variable: DIR Variable: LS Variable: All of the above
- Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Hint: Use epsilon value 0.0001. Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is:Equal #include <iostream>#include <cmath>using namespace std; int main() { double targetValue; double sensorReading; cin >> targetValue; cin >> sensorReading; if (/* Your solution goes here */) { cout << "Equal" << endl; } else { cout << "Not equal" << endl; } return 0;}Create an application that random 2 integers from 0 to 100. If a%b==0 print a/b, else rerollTo remove the value of a variable but keeping the variable in PowerShell, we can use this cmdlet: Group of answer choices Delete-Value Clear-Variable Clear-Value Remove-Variable
