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- Computer Science 1. Suppose that we have a 128-bit AES system: • 128-bit AES key; 2B7E151628AED2A6ABF7158809CF4F3C (in hexadecimal notation) • Plaintext: 3243F6A8885A308D313198A2E0370734 (in hexadecimal notation) a) What is the key for the first round in the 10-round AES? (Hint: W0 - W3) b) Construct the key schedule arising from the above key for second rounds c) What is the cyphertext of the above plaintext after one round? d) What is the cyphertext of the above plaintext after the second round?Perform the following operations (without converting to base 10). Show your work. a. 258 + 638b. 0x7BE3 + 0x45A7 c. 01012 + 10112 + 011012d. 1101002 - 0110102e. 1012 * 0112Q3 : Perform the following operation ( choose FIVE ) :-1- ( 7 – 3 ) using 2’s complement2- ( 111010 * 110011 )23- ( 572 )8 = ( ? )104- ( 111101.01101 )2 = ( ? )85- ( 56 )10 = ( ? )26- ( F9D )16 = ( ? )10
- Answer the following 4 questions with step by step explanations :1. Convert 870678(9) = x(27)2. Convert ABF(16) =x(64)3. Subtract APG(32) - 7RK(32) =4. Multiply BF(16)* AA(16) =Suppose DH contains (6B) hexadecimal, AH=(11001011)16 , CF=1, and CL contains 5, What are the values of DH AND DH,AH RCL DH, CL. Show the details of your work in the following table format. CL CF DHSubtract the followingFABC-ABCDABFD-98ACDFBC-15FF
- COH6SJ.Create a Hamming code (k, n) = (7,4) for the detection and correction of errors in word codeswhat is the first stage of R(10) if using data Eneryption Standard second stage R10 = 111001011100101111011110100001110110111101010010 K11= 001110101000101100101111110100100011101111111101 Select one: a. 11011111 01000000 11110001 11110001 01010101 01010100 10111111 b. 11011111 01000000 11110001 11110001 01010101 01011010 10101111 c. 11011111 01000000 10000001 11110001 01010101 01010100 10101111 d. 11011111 01000000 11110001 11110001 01010101 01010100 10101001 e. 11011111 01000000 11110001 11110001 01010101 01010100 10101111
- Assignment # 11. Convert 82ADh to decimal.2. Convert 11101b to decimal.3. Convert 2BD4h to decimal.4. Convert 95 to binary.5. Convert 2B3Ch to binary.6. Convert 1110101010b to hex.7. Add 3546d and 1872d.8. Add 5B39h and 7AF4h.9. Add 100101111b and 110110.10. Subtract 7283d from 9145d.11. Subtract BA94h from D26Fh.12. Subtract 0111b from 1001.13. Find one’s compliment of 5.14. Find two’s compliment of 5.15. Find two’s compliment of the two’s compliment of 5.16. In many applications, it saves time to memorize the conversions among small binary, decimal, and hex numbers. Fill in the blanks in the following table:Binary Decimal Hex_____ 9 _____1010 _____ __________ _____ D_____ 12 _____1110 _____ __________ _____ B 17. Convert the following binary and hex numbers to decimal:a. 1110b. 100101011101c. 46Ahd. FAE2Ch18. Convert the following numbers:a. 1001011 to hexb. 1001010110101110 to hexc. A2Ch to binaryd. B34Dh to binary19. Perform the following additions:a. 100101b + 10111bb. 100111101b…Explain what the following MIPS code does: (do not explain each line but explain what these two lines of codes do together) li $v0, 5syscallPlese using LZ77 encoding with a search window size of 8 and look ahead buffer of 4, encode the sequence abbdacdbbbbabba. Write down the output triples. Assume we will use <EOF> to indicate the end of the sequence.