Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) + 2 HC1(aq) ZnCl, (aq) + H, (g) How many milliliters of 4.50 M HCl(aq) are required to react with 4.05 g Zn(s)? volume:

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Zinc reacts with hydrochloric acid according to the reaction equation
Zn(s) + 2 HCl(aq) → ZnCl, (aq) + H, (g)
How many milliliters of 4.50 M HCl(aq) are required to react with 4.05 g Zn(s)?
volume:
mL
Transcribed Image Text:Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) + 2 HCl(aq) → ZnCl, (aq) + H, (g) How many milliliters of 4.50 M HCl(aq) are required to react with 4.05 g Zn(s)? volume: mL
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