Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3),(aq) + 2 NH,I(aq) Pbl,(s) + 2 NH,NO,(aq) > What volume of a 0.590 M NH41 solution is required to react with 703 mL of a 0.700 M Pb(NO3)2 solution? volume: How many moles of Pbl2 are formed from this reaction? moles: mol

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Chapter14: Chemical Equilibrium
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Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction
Pb(NO3),(aq) + 2 NH,I(aq)
Pbl,(s) + 2 NH,NO;(aq)
>
What volume of a 0.590 M NH,I solution is required to react with 703 mL of a 0.700 M Pb(NO3)2 solution?
volume:
m
How many moles of Pbl, are formed from this reaction?
moles:
mol Pb
Transcribed Image Text:Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3),(aq) + 2 NH,I(aq) Pbl,(s) + 2 NH,NO;(aq) > What volume of a 0.590 M NH,I solution is required to react with 703 mL of a 0.700 M Pb(NO3)2 solution? volume: m How many moles of Pbl, are formed from this reaction? moles: mol Pb
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