   Chapter 1, Problem 62P

Chapter
Section
Textbook Problem

A person walks 25.0° north of east for 3.10 km. How far due north and how far due east would she have to walk to arrive at the same location?

To determine
The travelled distance by the person along eastward and northward direction to arrive at the same location.

Explanation

The distance travelled by the person along eastward direction (Ax) .

Given Info: The person travelled a distance is 3.10km at 25° north of east.

Explanation:

The displacement of the person can be depicted in coordinate system as follows,

Formula to calculate the displacement along eastward direction is,

Ax=Acosθ

• A is the resultant displacement,
• θ is angle,

Substitute 3.1km for A , 25° for θ to find Ax .

Ax=(3.1km)(cos(25°))=2.81km

Thus, the displacement of the person along eastward direction is 2.81km .

The distance travelled by the person along northward direction (Ay)

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