# Determine the molarity of a NaOH solution when each of the following amounts of acid neutralizes 25.0 mL of the NaOH solution. a. 5.00 mL of 0.250 M HNO 3 b. 20.00 mL of 0.500 M H 2 SO 4 c. 23.76 mL of 1.00 M HCl d. 10.00 mL of 0.100 M H 3 PO 4

### General, Organic, and Biological C...

7th Edition
H. Stephen Stoker
Publisher: Cengage Learning
ISBN: 9781285853918

Chapter
Section

### General, Organic, and Biological C...

7th Edition
H. Stephen Stoker
Publisher: Cengage Learning
ISBN: 9781285853918
Chapter 10, Problem 10.149EP
Textbook Problem
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## Determine the molarity of a NaOH solution when each of the following amounts of acid neutralizes 25.0 mL of the NaOH solution. a. 5.00 mL of 0.250 M HNO3 b. 20.00 mL of 0.500 M H2SO4 c. 23.76 mL of 1.00 M HCl d. 10.00 mL of 0.100 M H3PO4

(a)

Interpretation Introduction

Interpretation:

Molarity of NaOH solution that reacts with 5.00 mL of 0.250 M HNO3 has to be determined.

Concept-Introduction:

Acid–base titration: It consists of a neutralization reaction where a measured volume of a known concentrated an acid or a base is used for determining the concentration of an unknown solution of base or acid with known volume.  The known concentrated solution is called the titrant, while the unknown concentrated solution is called the analyte.

Molarity: The concentration for solutions is expressed in terms of molarity as follows,

Molarity = No. of moles of soluteVolume of solution in L

### Explanation of Solution

Given data is shown below:

Reaction : NaOH + HNO3  NaNO3 + H2OMolarity of HNO3= 0.250 MVolume of HNO3= 5.00 mL = 5.00×103 LVolume of NaOH= 25.0 mL = 25.0×103 L

Number of moles of HNO3 reacted is determined as follows,

No. of moles = Molarity×VolumeNo. of moles = (0.250 mol/L)(5.00×103 L)= 1.25×103 mol HNO3

From the reaction it is clear that one mole of NaOH reacts with one mole of HNO3

(b)

Interpretation Introduction

Interpretation:

Molarity of NaOH solution that reacts with 20.00 mL of 0.500 M H2SO4 has to be determined.

Concept-Introduction:

Acid–base titration: It consists of a neutralization reaction where a measured volume of a known concentrated an acid or a base is used for determining the concentration of an unknown solution of base or acid with known volume.  The known concentrated solution is called the titrant, while the unknown concentrated solution is called the analyte.

Molarity: The concentration for solutions is expressed in terms of molarity as follows,

Molarity = No. of moles of soluteVolume of solution in L

(c)

Interpretation Introduction

Interpretation:

Molarity of NaOH solution that reacts with 23.76 mL of 1.00 M HCl has to be determined.

Concept-Introduction:

Acid–base titration: It consists of a neutralization reaction where a measured volume of a known concentrated an acid or a base is used for determining the concentration of an unknown solution of base or acid with known volume.  The known concentrated solution is called the titrant, while the unknown concentrated solution is called the analyte.

Molarity: The concentration for solutions is expressed in terms of molarity as follows,

Molarity = No. of moles of soluteVolume of solution in L

(d)

Interpretation Introduction

Interpretation:

Molarity of NaOH solution that reacts with 10.00 mL of 0.100 M H3PO4 has to be determined.

Concept-Introduction:

Acid–base titration: It consists of a neutralization reaction where a measured volume of a known concentrated an acid or a base is used for determining the concentration of an unknown solution of base or acid with known volume.  The known concentrated solution is called the titrant, while the unknown concentrated solution is called the analyte.

Molarity: The concentration for solutions is expressed in terms of molarity as follows,

Molarity = No. of moles of soluteVolume of solution in L

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