   # What volume of ethylene glycol (C 2 H 6 O 2 ), a nonelectrolyte, must be added to 15.0 L water to produce an antifreeze solution with a freezing point of −25.0°C? What is the boiling point of this solution? (The density of ethylene glycol is 1.11 g/cm 3 , and the density of water is 1.00 g/cm 3 .) ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 10, Problem 70E
Textbook Problem
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## What volume of ethylene glycol (C2H6O2), a nonelectrolyte, must be added to 15.0 L water to produce an antifreeze solution with a freezing point of −25.0°C? What is the boiling point of this solution? (The density of ethylene glycol is 1.11 g/cm3, and the density of water is 1.00 g/cm3.)

Interpretation Introduction

Interpretation:

The volume of Ethylene glycol that has to be added to water has to be calculated and the boiling point of the solution has to be calculated.

Concept Introduction:

Molality of the solution can give by number of moles of solute present in the 1 kilogram of solvent.

Molality =Number of moles ofsolute1kg of solvent

Elevation of boiling point: Elevation of boiling point of a liquid is occurrence that boiling point of a liquid would be greater when another substance is added to it. Resulting, the boiling point becomes higher than the pure solvent.

ΔTb = Kb

Where,

Kb= Constant for elevation of boiling point

m = Molality of the solution

### Explanation of Solution

To calculate molality of Ethylene glycol:

Record the given data

Volume of water = 15L

Freezing point of antifreeze solution= 250C

Density of Ethylene glycol = 1.11g/cm3

Density of water = 1.00 g/cm3

m =ΔTfKf

=25.00C1.860C kg/mol=13.4 mol C2H6O2/kg

To calculate moles of Ethylene glycol needed to 15Lof water:

15.0L H2×1.00 kg H2OLH2O×13.4molC2H6kgH2O

=201mol C2H6O2

To calculate volume of Ethylene glycol:

Molecular weight of Ethylene glycol = 62

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