   Chapter 11, Problem 53P

Chapter
Section
Textbook Problem

Measurements on two stars indicate that Star X has a surface temperature of 5 727°C and Star Y has a surface temperature of 11 727°C. If both stars have the same radius, what is the ratio of the luminosity (total power output) of Star Y to the luminosity of Star X? Both stars can be considered to have an emissivity of 1.0.

To determine
The ratio of the luminosity of Star Y to the luminosity of star X.

Explanation

Given info: Surface temperature of Star X is 5727°C and Surface temperature of Star Y is 11727°C and both the stars are of same radius.

Formula to calculate the net power radiated by the Star X is,

PX=σAeTX2

• PX is the power radiated by the Star X,
• σ is Stefan’s – Boltzmann constant,
• A is the surface area of the Star,
• e is emissivity of the Star,
• TX is the surface temperature of star Y.

Formula to calculate the net power radiated by the Star X is,

PY=σAeTY2

• PY is the power radiated by the Star X,
• σ is Stefan’s – Boltzmann constant,
• A is the surface area of the Star,
• e is emissivity of the Star,
• TY is the surface temperature of star Y.

Equate both power radiate equation.

PYPX=σAeTY2σAeTX2

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 