   # What is the molarity of a solution that contains 28 g of NaNO 3 in 3 .2 L of solution? ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 12, Problem 38E
Textbook Problem
1 views

## What is the molarity of a solution that contains 28 g of NaNO 3 in 3 .2 L of solution?

Interpretation Introduction

Interpretation:

The molarity of the given solution is to be calculated.

Concept Introduction:

The same solute and solvent can form a number of combinations by varying their amounts. These combinations can be differentiated in terms of concentration of solution. The amount of solute present in a given amount of solvent is defined as its concentration.

The number of moles is calculated as follows:

Number of moles =Mass Molar mass

Molarity is the number of moles of solute present in one liter of a solution, and is expressed as follows:

Molarity=Number of molesVolume of solution

### Explanation of Solution

Given Information: Mass of sodium nitrate is 28 g. The volume of the solution is 3.2 L.

The number of moles is calculated by the division of moles by molar mass as follows:

Number of moles =Mass Molar mass

The molar mass of NaNO3=85 g/mol

Number of moles of NaNO3=Mass of NaNO3 Molar mass of NaNO3Number of moles of NaNO3=28 g 85 g/mole=0

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