   # How many grams of sucrose ( C 12 H 22 O 11 ) are present in 2.8 L of a 2.2-M sucrose solution? ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 12, Problem 39E
Textbook Problem
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## How many grams of sucrose ( C 12 H 22 O 11 ) are present in 2.8 L of a 2.2-M sucrose solution?

Interpretation Introduction

Interpretation:

The mass of sucrose present in given solution is to be calculated.

Concept Introduction:

The same solute and solvent can form a number of combinations by varying their amounts. These combinations can be differentiated in terms of concentration of solution. The amount of solute present in a given amount of solvent is defined as its concentration.

The number of moles is calculated as follows:

Number of moles =Mass Molar mass

Molarity is the number of moles of solute present in one liter of a solution, and is expressed as follows:

Molarity=Number of molesVolume of solution

### Explanation of Solution

Given Information: Molarity of the sucrose solution is 2.2 M. The volume of the solution is 2.8 L.

Molarity is defined as the number of moles of a solute present in 1L of a solution. The number of moles is calculated by the division of moles by molar mass as follows:

The number of moles is calculated using molarityas follows:

Molarity=Number of molesVolume of solution

Molarity=Number of moles of sucroseVolume of solution2.2 moles/ L=Number of moles of sucrose2.8 L Number of moles of sucrose=2.2 moles/L×2.8 L=6

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