   Chapter 13, Problem 31PS

Chapter
Section
Textbook Problem

What is the boiling point of a solution composed of 15.0 g of CHCl3 and 0.515 g of the nonvolatile solute acenaphthene, C12H10, a component of coal tar?

Interpretation Introduction

Interpretation: The Boiling point of solution to be identified.

Concept introduction:

Boiling point elevation: The boiling point of the solution varies with the solute concentration.

Elevation in boiling point = ΔTbp= Kbp. msolute,where,Kbpismolal boiling point elevation constant,msoluteis molality of solute

Explanation

Given data:

Massofacenapthene(solute) =0.515gMass of CHCl3 = 15 g Boilingpointofsolution= ?Boiling point of CHCl3 = 61.70oCKbpofWater=+3.63oC/m

No.ofmoles=massmolarmass

Mole of solute = 0.515g154.2g/mol=0.0033 mol

Calculation of the molality of solute  in solution(m):_molality = Moles of solute (mol)Amount of solvent(in kg) = (0.0033 mol)0.015 kg= 0.22m

Boiling point elevation:_Elevation in boiling point = ΔTbp= Kbp

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