# Suppose that 250.0 mL of a basic solution is 0.100 M in KOH. What volume of a 0 .200-M HCl solution would be required to completely neutralize the basic solution?

### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

Chapter
Section

### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 13, Problem 44E
Textbook Problem
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## Suppose that 250.0 mL of a basic solution is 0.100 M in KOH. What volume of a 0 .200-M HCl solution would be required to completely neutralize the basic solution?

Interpretation Introduction

Interpretation:

The volume of 0.200 M HCl solution required to neutralize all the given basic solution is to be calculated.

Concept Introduction:

Antacids are the substances that neutralize the acidity of the stomach. They work differently from other acids, by reducing the secretion of stomach acids.

Antacids can be in the form of liquid, tablets, or chewable tablets.

These are used to treat indigestion, heartburn, the burning sensation in the chest, and acid reflux in stomach.

Molar mass is the mass of a substance, in grams, present in one mole of the substance.

Molarity and number of moles are related to each other by the formula:

Number of moles= molarity× volume of solution in litres

### Explanation of Solution

Given information: 250 mL of 0.100 M KOH and 0.200 M HCl

The neutralization reaction of KOH is as follows:

KOH+HCl KCl+H2O

The moles of hydroxide ions are calculated as follows:

Number of moles= molarity× volume of solution in litres

Number of moles of OH=0.100 M×0.250 L=2.5×102 mol

In the neutralization reaction, number of moles of H+ and OH are equal, therefore,

Number of moles of H+=2

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