   Chapter 13, Problem 59GQ

Chapter
Section
Textbook Problem

Concentrated aqueous ammonia has a molarity of 14.8 mol/L and a density of 0.90 g/cm3. What is the molality of the solution? Calculate the mole fraction and weight percent of NH3.

Interpretation Introduction

Interpretation: The weight percentage and mole fraction of NH3 are to be determined.

Concept introduction:

Mole fraction: Amount of that component divided by the total amount of all of the components of the mixture ( nA +  nB +  n...).

Mole fraction of A (χA)= nA nA +  nB +  n...

Weight percent: The mass of one component divided by the total mass of the mixture, multiplied by 100%

weight % A = Mass of A Mass of A + Mass of B + Mass of C + ...×100%

The number of moles of any substance can be determined using the equation

Numberofmole=GivenmassofthesubstanceMolarmass

Explanation

Given,

Molarity of aqueous ammonia solution is 14.8mol/L

Density of aqueous ammonia solution is 0.90g/cm3

Molar mass of ammonia is 17.03 g/mol

Molar mass of water is 18.02 g/mol

The number of moles of ammonia in 1L of solution, nammonia is 14.8moles

Mass of ammonia=numberofmoles×molarmass=14.8moles×17.03 g/mol=252.044g

Mass of ammonia solution is 0.90×1000=900g

Mass of water is 900g251.6=684.4g

The number of moles of any substance can be determined using the equation

Numberofmole=GivenmassofthesubstanceMolarmass

Number of moles of water is,

nwater=684

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