The following data represent the results of a repeated-measures study comparing different viewing distances for a 42-inch-high-definition television. Four viewing distances were evaluated, 9 feet, 12 feet, 15 feet, and 18 feet. Each participant was free to move back and forth among the four distances while watching a 30-minute video on the television. The only restriction was that each person had to spend at least 2 minutes watching from each of the four distances. At the end of the video, each participant rated the all off of the viewing distances on a scale fro

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section: Chapter Questions
Problem 8RE
icon
Related questions
icon
Concept explainers
Topic Video
Question

The following data represent the results of a repeated-measures study comparing different viewing distances for a 42-inch-high-definition television. Four viewing distances were evaluated, 9 feet, 12 feet, 15 feet, and 18 feet. Each participant was free to move back and forth among the four distances while watching a 30-minute video on the television. The only restriction was that each person had to spend at least 2 minutes watching from each of the four distances. At the end of the video, each participant rated the all off of the viewing distances on a scale from 1 (very bad, definitely need to move closer or father way) to 7 (excellent, perfect viewing distance).

Use a repeated-measures ANOVA with alpha = 0.05 to determine whether there is significant difference among the four viewing distances.

 

Viewing Distance
Person
Person
9 Feet
12 Feet
15 Feet
18 Feet
Totals
n = 5
k=4
A
3
4
7
P= 20
В
3
6.
3
P= 12
C
2
1
4
P= 12
N= 20
D
1
4
3
P= 8
G= 60
E
1
3
4
P= 8
ΣΧ262
T= 5
T = 10
T= 25
T= 20
SS = 8
SS = 8
SS = 10
SS = 6
Transcribed Image Text:Viewing Distance Person Person 9 Feet 12 Feet 15 Feet 18 Feet Totals n = 5 k=4 A 3 4 7 P= 20 В 3 6. 3 P= 12 C 2 1 4 P= 12 N= 20 D 1 4 3 P= 8 G= 60 E 1 3 4 P= 8 ΣΧ262 T= 5 T = 10 T= 25 T= 20 SS = 8 SS = 8 SS = 10 SS = 6
Expert Solution
Step 1

Test Hypotheses:

There are 3 groups of viewing distances. Denote the true average of the four groups of viewing distances 9-feet, 12-feet, 15-feet and 18-feet as μ1, μ2, μ3, and μ4, respectively.

The hypotheses to be tested are:

Null hypothesis:

H0: μ1 = μ2 = μ3 = μ4.

That is, the mean of all the four groups of viewing distances are equal.

Alternative hypothesis:

Ha: At least one of the mean of four viewing distance groups differs from the other.

Evidently, the test is for equality of 4 means. The means take numerical values.

Now, a one-way ANOVA of repeated measures is the most suitable for testing the equality of several means, provided the assumptions of independence of observations, normality of residuals and homogeneity of variances are satisfied.

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 6 images

Blurred answer
Knowledge Booster
Centre, Spread, and Shape of a Distribution
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
College Algebra
College Algebra
Algebra
ISBN:
9781337282291
Author:
Ron Larson
Publisher:
Cengage Learning