a) What is the mole fraction of the solvent?b) What is the %m/m of the solution?c) What is the molarity of the solution? Consider Palmitic acid C16H3202, a common fatty acid used in the manufacture of soap. Asolution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzeneC6H6. The density of the resulting solution is 0.902 g/mL.Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass =78 g/mol and density = 0.879 g/mL)%3D

A solution consists of solute and solvent. A solute is defined as the component that is present in…

Answered: a) What is the mole fraction of the…

a) What is the mole fraction of the solvent? b) What is the %m/m of the solution? c) What is the molarity of the solution?

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 35QAP: 35. For each of the following solutions, the mass of solute is given, followed by the total volume...

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Question

a) What is the mole fraction of the solvent?
b) What is the %m/m of the solution?
c) What is the molarity of the solution?

Consider Palmitic acid C16H3202, a common fatty acid used in the manufacture of soap. A
solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene
C6H6. The density of the resulting solution is 0.902 g/mL.
Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass =
78 g/mol and density = 0.879 g/mL)
%3D

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Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) A. What is the molarity of the solution? B. How many mL of the 2M palmitic acid stock solution will you need? Final answer must be rounded off to 2 decimal places, and shall NOT have any units.
Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) What is the molarity of the solution? How many mL of the 2M palmitic acid stock solution will you need? How many mL of solvent do you need to add to the amount gotten from the 2M Palmitic acid stock solution in order to prepare 250 mL total volume of your desired solution?
Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) What is the molarity of the solution? Final answer must be rounded off to 2 decimal places, and shall NOT have any unit. Based from the Molarity of the palmitic acid solution that you were able to solve earlier, how will you prepare 250 mL of the said molar concentration, if you have an available 2M stock solution of Palmitic acid? How many mL of the 2M palmitic acid stock solution will you need? Final answer must be rounded off to 2 decimal places, and shall NOT have any units