9th Edition
Steven S. Zumdahl
ISBN: 9781133611097




9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

Consider the decomposition of the compound C5H6O3 as follows:

C 5 H 6 O 3 ( g ) C 2 H 6 ( g ) + 3 CO ( g )

When a 5.63-g sample of pure C5H6O3(g) was sealed into an otherwise empty 2.50-L flask and heated to 200°C, the pressure in the flask gradually rose to 1.63 atm and remained at that value. Calculate K for this reaction.

Interpretation Introduction

Interpretation: The decomposition reaction, mass of C5H6O3 , volume of flask and rise in pressure is given. The value of equilibrium constant is to be calculated.

Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction. When the equilibrium constant is expressed in terms of pressure, it is represented as Kp .

To determine: The value of equilibrium constant.




The rise in pressure of given reaction is 1.63atm .

Mass of C5H6O3 is 5.63g .

Volume of flask is 2.50L .

The given temperature is 200°C .

The molar mass of C5H6O3 ,


The conversion of degree Celsius (°C) into Kelvin (K) is done as,



The conversion of 200°C into Kelvin is,


The stated reaction is,


The number of moles is calculated using the formula,


Substitute the values of given mass and molar mass of C5H6O3 in above equation.


It is the initial moles of C5H6O3 .

The initial moles of product is,


The formula of ideal gas law is,



  • P is total pressure.
  • V is volume.
  • ntotal is total moles.
  • R is the universal gas constant (0.08206Latm/Kmol) .
  • T is absolute temperature.

Substitute the values of P,V,R and T in above equation.


Simplify the above equation,


It is assumed that the change in pressure of C2H6(g) is x .

On the reaction with one molecule of C5H6O3 , the equilibrium reaction is,


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