   Chapter 14, Problem 90E

Chapter
Section
Textbook Problem

# Calculate [OH−], pOH, and pH for each of the following.a. 0.00040 M Ca(OH)2b. a solution containing 25 g KOH per literc. a solution containing 150.0 g NaOH per liter

(a)

Interpretation Introduction

Interpretation: The [OH] , pH and the pOH value for the given solutions is to be calculated.

Concept introduction: The pH of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution. A logarithmic scale is used on which, the value 7 corresponds to a neutral species, a value less than 7 corresponds to an acid and a value greater than 7 corresponds to a base.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

To determine: The [OH] , pH and the pOH value for 0.00040MCa(OH)2 .

Explanation

Explanation

Given

0.00040MCa(OH)2 solution.

Ca(OH)2 is a strong base. Therefore, it will completely dissociate into ions.

Therefore, [OH] =(2×0.00040)M=0.00080M_

The pOH of a solution is calculated by the formula,

pOH=log<

(b)

Interpretation Introduction

Interpretation: The [OH] , pH and the pOH value for the given solutions is to be calculated.

Concept introduction: The pH of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution. A logarithmic scale is used on which, the value 7 corresponds to a neutral species, a value less than 7 corresponds to an acid and a value greater than 7 corresponds to a base.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

To determine: The [OH] , pH and the pOH value for a solution containing 25g KOH per liter.

(c)

Interpretation Introduction

Interpretation: The [OH] , pH and the pOH value for the given solutions is to be calculated.

Concept introduction: The pH of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution. A logarithmic scale is used on which, the value 7 corresponds to a neutral species, a value less than 7 corresponds to an acid and a value greater than 7 corresponds to a base.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

To determine: The [OH] , pH and the pOH value for a solution containing 150.0g NaOH per liter.

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