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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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If 10. g of AgNO3 is available, what volume of 0.25 M AgNO3 solution can be prepared?

Interpretation Introduction

Interpretation:

The volume of 0.25M

AgNO3 solution that can be prepared is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

Moles=MassgMolarmass

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteVolumeofsolutionL.

Explanation

The mass and molarity of AgNO3 solution is given to be 10.g and 0.25M respectively.

The molar mass of AgNO3 is 169.87g/mol.

The number of moles is calculated by the formula,

Moles=MassgMolarmass        (1)

Substitute the values of mass and molar mass in the equation (1).

Moles=10.g169.87g/mol=0

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