   Chapter 15, Problem 27P

Chapter
Section
Textbook Problem

A charged dust particle at rest in a vacuum is held motionless by an upward-directed 475-N/C electric field. If the dust particle has a mass of 7.50 × 10−10 kg, find (a) the charge on the dust particle and (b) the number of electrons that must be added to neutralize it.

(a)

To determine
The charge on the dust particle.

Explanation

Given info: The mass of the dust particle is 7.50×1010kg . Electric field strength is 475 N/C.

Formula to calculate the magnitude of acceleration of the proton is,

q=mgE

• g is the acceleration due to gravity.
• E is the electric field.
• m is the mass of proton.

Substitute 9.8ms2 for g, 475 N/C for E and 7.50×1010kg for m

(b)

To determine
The number of required electrons.

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