The value of the equilibrium constant for the following reaction is 115.                           A + 2B ↔  3C + D                                                               What is the value of the equilibrium constant for the reaction below?                         2A + 4B ↔  6C + 2D A. K = 115 B. K = (115)2 = 1.3 x 104      C. K = (115)1/2 = 10.7                          D.  K = (2 x 345)2 = 5.29 x 105                         E. K = 2 x (345)2 = 2.64 x 105

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