   Chapter 15, Problem 45P

Chapter
Section
Textbook Problem

An electric field of intensity 3.50 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if (a) the plane is parallel to the yz-plane, (b) the plane is parallel to the xy-plane, and (c) the plane contains the y-axis and its normal makes an angle of 40.0° with the x-axis.

(a)

To determine
The electric flux.

Explanation

Given info: The electric field (E) is 3.5 kN/C. The width (w) is 0.350 m and length (l) is 0.700 m. The angle between the electric field and area vector ( θ ) is 0ο (Plane is parallel to yz plane)

Formula to calculate the electric flux is,

ϕE=EAcosθ

The area is,

A=wl

Therefore,

ϕE=Ewlcosθ

Substitute 3.5 kN/C for E, 0.350 m for w, 0.700 m for l and 0ο for θ .

ϕE=(3

(b)

To determine
The electric flux.

(c)

To determine
The electric flux.

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