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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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70. What volume of a 0.500 M NaOH solution would be required to neutralize 40.0 mL of a 0.400 M H2SO4 solution?

Interpretation Introduction

Interpretation:

The volume of 0.500M

NaOH solution required to neutralize 40.0mL of 0.400MH2SO4 solution is to be calculated.

Concept Introduction:

A chemical reaction that occurs between acid and base is known as neutralization reaction. An addition of the base into an acid results in the neutralization of an acid. During neutralization reaction, water is produced as a side product.

Explanation

The value of M1, V1 and M2 is given to be 0.400M, 40.0mL and 0.500M respectively.

The balanced equation when NaOH reacts with H2SO4 is shown below.

2NaOH+H2SO42H2O+Na2SO4

The above reaction indicates that two equivalents of NaOH required to neutralize one equivalent of H2SO4.

The relationship between concentration and volume of NaOH and H2SO4 solutions is shown below.

2×M1V1=M2V2

Where,

  • M1 is the concentration of H2SO4 solution.
  • V1 is the volume of H2SO4 solution

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