   Chapter 15.8, Problem 15.10SC ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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# ercise 15.10 Calculate the normality of a solution containing 23.6 g of KOH in 755 mL of solution.

Interpretation Introduction

Interpretation:

The normality of the solution having 23.6 g of KOH in 755 mL of solution should be calculated.

Concept Introduction:

Normality of the solution is equal to the ratio of equivalent of solute to the volume of solution in litres.

The mathematical expression is given by:

Normality = equivalent of solute volume of solution in litres.

Explanation

First, calculate the equivalents of KOH by dividing given mass by the molar mass of KOH.

Equivalents of KOH = 26.0 g×1 equivalent KOH56.1 g KOH=0.420 equivalent KOH

Now, convert the volume into litres

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