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Statistics for The Behavioral Scie...

10th Edition
Frederick J Gravetter + 1 other
Publisher: Cengage Learning
ISBN: 9781305504912

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Chapter
Section
BuyFindarrow_forward

Statistics for The Behavioral Scie...

10th Edition
Frederick J Gravetter + 1 other
Publisher: Cengage Learning
ISBN: 9781305504912
Chapter 16, Problem 1P
Textbook Problem
78 views

Sketch a graph showing the line for the equation Y = 2 X 1 .On the same graph, show the line for Y = X + 8 .

To determine

To graph:

Equation Y = 2X1 and Y = X + 8 in the same plot.

Answer to Problem 1P

Solution:

We find the line Y=2X1 passing through points (2,3) and (1,1) and the line Y=X+8 passing through points (5,3) and (1,7). Both the lines are plotted on the same graph. We find that both the graphs intersect each other.

Explanation of Solution

Steps:

  • For equation Y=2X-1, we need to find two points that lie on this line
  • So let X= 2, We get:
  • Y=2x21 Y=41 Y=3
  • Similarly, let X = 1, we get:
  • Y=2x11 Y=21 Y=1
  • Hence we get two points for equation Y=2X1 are: (2,3) and (1,1)
  • Similarly for equation Y=X+8 we need to find two points
  • For X = 5, we get:
  • Y=5+8 Y=3
  • And for X =1, we get:
  • Y=1+8 Y=7
  • Thus the two points for the equation Y=X+8 are: (5,3) (1,7)
  • Plot x axis horizontally, and Y axis vertically and label both of them from 1 to 10
Statistics for The Behavioral Sciences (MindTap Course List), Chapter 16, Problem 1P

Conclusion:

Thus with the help of equations, we can plug in some values of X as we want and predict the Y values. This gives us he points through with the line will pass. It helps us plot the line on the graph. If we use similar values of X it helps us to plot two different lines on the same graph.

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