   Chapter 16, Problem 39P

Chapter
Section
Textbook Problem

Find (a) the equivalent capacitance of the capacitors in Figure P16.39, (b) the charge on each capacitor, and (c) the potential difference across each capacitor. Figure P16.39

(a)

To determine
The equivalent capacitance.

Explanation

The capacitors 6.00μF and 2.00μF are connected in parallel combination. The equivalent capacitance is,

Cp=C6.00μF+C2.00μF

The capacitances Cp , C8.00μF and C8.00μF are in series combination. The total equivalent capacitance is,

1Ceq=1Cp+1C8.00μF+1C8.00μF

Therefore,

1Ceq=1C6.00μF+C2.00μF+1C8.00μF+1C8

(b)

To determine
The charge on each capacitor.

(c)

To determine
The potential difference across each capacitor.

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