   Chapter 16, Problem 60AP

Chapter
Section
Textbook Problem

For the system of four capacitors shown in Figure P16.41, find (a) the total energy stored in the system and (b) the energy stored by each capacitor. (c) Compare the sum of the answers in pan (b) with your result to part (a) and explain your observation.

(a)

To determine
The total energy stored.

Explanation

The capacitors 6.00μF and 3.00μF are connected in series combination. The equivalent capacitance is,

Cpt=C6.00μFC3.00μFC6.00μF+C3.00μF

The capacitors 2.00μF and 4.00μF are connected in series combination. The equivalent capacitance is,

Cpb=C2.00μFC4.00μFC2.00μF+C4.00μF

The capacitances Cpt and Cpb are in parallel combination. The total equivalent capacitance is,

Ceq=Cpt+Cpb

Therefore,

Ceq=(C6.00μFC3.00μFC6.00μF+C3.00μF)+(C2.00μFC4.00μFC2.00μF+C4.00μF)

Substitute 6.00μF for C6

(b)

To determine
The energy stored by each capacitor.

(c)

To determine
The sum of energy stored by each capacitor.

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