   Chapter 16, Problem 64AP

Chapter
Section
Textbook Problem

Two charges of 1.0 μC and −2.0 μC are 0.50 m apart at two vertices of an equilateral triangle as in Figure P 16.64. (a) What is the electric potential due to the 1.0-μC charge at the third vertex, point P? (b) What is the electric potential due to the −2.0-μC charge at P? (c) Find the total electric potential at P. (d) What is the work required to move a 3.0-μC charge from infinity to P? Figure P 16.64

(a)

To determine
The electric potential due to 1.0μC charge at P.

Explanation

Given info: The positive charge ( q1 ) is 1.0μC . The negative charge ( q2 ) is 2.0μC . The distance of separation (r) is 0.50 m.

Formula to calculate the electric potential is,

V1=keq1r

Substitute 8.99×109 Nm2C2 for ke , 1.0μC for q1 and 0.50 m for r.

V1=(8.99×109 Nm2C2)(1

(b)

To determine
The electric potential due to 2.0μC charge at P.

(c)

To determine
The total electric potential at P.

(d)

To determine
The work required to move a 3.0μC charge from infinity to P.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 