   # A solution containing Pt 4+ is electrolyzed with a current of 4.00 A. How long will it take to plate out 99% of the platinum in 0.50 L of a 0.0 10-M solution of Pt 4+ ? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 17, Problem 104E
Textbook Problem
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## A solution containing Pt4+ is electrolyzed with a current of 4.00 A. How long will it take to plate out 99% of the platinum in 0.50 L of a 0.0 10-M solution of Pt4+?

Interpretation Introduction

Interpretation:

The electrolysis of solution containing Pt+4 by passing a given amount of current is given. The time taken to plate out 99% of the platinum in 0.50L of a 0.010M solution of Pt+4 is to be calculated.

Concept introduction:

The non-spontaneous reaction takes place in an electrolytic cell in which there occurs conversion of electrical energy into chemical energy and this is used for the electrolysis of a metal.

The charge generated in the cell is calculated as,

Q=It

When electricity is passed through an electrolytic cell, at that time the amount of the substance that is liberated at an electrode is given by,

W=ZQ=ZIt

The value of Z is given as,

Z=Molarmassn×96,485

To determine: The time taken to plate out 99% of the platinum in 0.50L of a 0.010M solution of Pt+4 .

### Explanation of Solution

Given information

The given current is 4.00A .

The given concentration is 0.010M .

The given volume is 0.50L .

The reaction Platinum undergoes during electrolysis is,

Pt+4+4e-Pt

The reaction involves the transfer of 4 moles of electron.

The concentration of Pt in solution is given as,

Concentration=NumberofmolesVolumeofsolutioninlitres

Rearrange the equation to obtain the number of moles of Pt and substitute the value of concentration and volume of the given solution as,

Numberofmoles=Concentration×Volumeofsolutioninlitres=0.010M×0.50L=5×10-3moles

The number of moles of Platinum is calculated as,

Numberofmoles=Givenmass(W)Molarmass

Rearrange the equation to obtain the value of the given mass (W) and substitute the value of number of moles and molar mass as,

Givenmass(W)=Numberofmoles×Molarmass=5×10-3moles×195.08gmol=0.9754g

The amount of Platinum present in 99% of 0.9754g of Pt is,

=0.9754g×99100= 0

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