A titration of 25.0 mL of a solution of the weak base aniline, C6H5NH2, requires 25.67 mL of 0.175 M HCl to reach the equivalence point.
C6H5NH2(aq) + H3O+(aq) ⇄ C6H5NH3+(aq) + H2O(ℓ)
(a) What was the concentration of aniline in the original solution?
(b) What are the concentrations of H3O+, OH−, and C6H5NH3+ at the equivalence point?
(c) What is the pH of the solution at the equivalence point?
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