   Chapter 17, Problem 3P

Chapter
Section
Textbook Problem

In the Bohr model of the hydrogen atom, an electron in the lowest energy state moves at a speed equal to 2.19 × 106 m/s in a circular path having a radius of 5.29 × 10−11 m. What is the effective current associated with this orbiting electron?

To determine
The effective current associated with orbiting electron.

Explanation

Given Info: Electron in its lowest energy state moves with the velocity 2.19×106ms-1 in a circular orbit of radius 5.29×1011m , Electron in its lowest energy state moves with the velocity 2.19×106ms-1 in a circular orbit of radius 5.29×1011m .

Explanation:

Formula to calculate the time period of electron is,

T=2πrv

• T is the time period of electron,
• r is the radius of circular orbit,
• v is the velocity of electron,

Substitute 3.14 for π , 5.29×1011m for r and 2.19×106ms-1 for v in the above equation to find T .

T=2(3.14)(5.29×10-11m)2.19×106ms-1=1

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 