Chapter 18, Problem 23P

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# In the circuit of Figure P18.23, determine (a) the current in each resistor, (b) the potential difference across the 2.00 × 102-Ω resistor, and (c) the power delivered by each battery.Figure P18.23

(a)

To determine
The current in each resistor I1,I2,I3,I4

Explanation

Given Info:

Explanation:

Resistance R1 is 2.00Ã—102â€‰Î© , Resistance R2 is 80.0â€‰Î© , Resistance R3 is 20.0â€‰Î© , Resistance R4 is 70.0â€‰Î© , Voltage Îµ1 is 40.0â€‰V , Voltage Îµ2 is 3.60Ã—102â€‰V , and Voltage Îµ3 is 80.0â€‰V .

The below figure shows the path of current in the circuit

• Îµ1,Îµ2,Îµ3 is voltage in the circuits
• R1,R2,R3,R4 is corresponding resistance in the circuits
• I1,I2,I3,I4 is corresponding current in the circuits

Apply Kirchhoffâ€™s voltage law

From the left loop dbacd,

âˆ’Îµ1âˆ’R1I1+R2I2=0

Substitute, 2.00Ã—102â€‰Î© for R1 , 80.0â€‰Î© for R2 , 40.0â€‰V for Îµ1 , in the above equation to find the expression for I2

From the middle loop cefdc,

Îµ1+Îµ2âˆ’R2I2âˆ’R3I3=0

Substitute, 80.0â€‰Î© for R2 , 20.0â€‰Î© for R3 40.0â€‰V for Îµ1 , 3.60Ã—102â€‰V for Îµ2 in the above equation to find the expression for I3

From the right loop ghbag

âˆ’Îµ3+R4I4âˆ’R1I1=0

Substitute, 2

(b)

To determine
The potential difference (V1) across in 2.00×102Ω is R1

(c)

To determine
The Power delivered by each battery.

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