   Chapter 18, Problem 60GQ

Chapter
Section
Textbook Problem

The enthalpy of vaporization of liquid diethyl ether, (C2H5)2O, is 26.0 kJ/mol at the boiling point of 35.0 °C. Calculate ΔS° for a vapor-to-liquid transformation at 35.0 °C.

Interpretation Introduction

Interpretation:

The value of ΔrS for vapour-to-liquid transformation of diethylether under given conditions should be calculated.

Concept introduction:

The Gibbs free energy or the free energy change is a thermodynamic quantity represented by ΔrG. It is related to entropy and entropy by the following expression,

ΔrG=ΔrHTΔrS

Here, ΔrH is the change in enthalpy and ΔrS is the change in entropy.

The value of ΔrG is zero at the boiling point of the liquid. Thus the entropy change can be written as,

ΔrS=ΔrHT

Explanation

The ΔrS for a vapour-to-liquid transformation of diethyl ether is calculated below.

The given reaction is,

(C2H5)2O(l)(C2H5)2O(v)

The boiling point is 35°C.

The enthalpy of vaporization of liquid diethyl ether is 26.0 kJ/mol.

The expression for free energy change is,

ΔrG=ΔrHTΔrS

At the boiling point the value of ΔrG is zero

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