   Chapter 19, Problem 13P

Chapter
Section
Textbook Problem

An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.235 T. If the kinetic energy of the electron is 3.30 × 10−19 J, find (a) the speed of the electron and (b) the radius of the circular path.

a)

To determine
The speed of the electron.

Explanation

Given info: The magnitude of the magnetic field is 0.235T . The electron moves ina circular path perpendicular to the magnetic field. The kinetic energy of the electron is 3.30×1019J .

Explanation:

The kinetic energy of electron is defined as,

KE=12mv2

• m is the mass of electron
• v is the speed of the electron

Re-arranging for v ,

v=2(KE)m

Substitute 3.30×1019J for KE and 9

b)

To determine
The radius of the circular path of electron.

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