An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 4.00 mT. The angular momentum of the electron about the center of the circle is 6.00 x 1025 J-s. (a) Determine the radius of the circular path. cm (b) Determine the speed of the electron. m/s

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Author:Raymond A. Serway, Chris Vuille
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Chapter19: Magnetism
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Problem 66AP: An electron moves in a circular path perpendicular to a constant magnetic field of magnitude 1.00...
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An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 4.00 mT. The angular momentum of the electron about the center of the circle is 6.00
x 10-25 1.s.
(a) Determine the radius of the circular path.
cm
(b) Determine the speed of the electron.
m/s
Transcribed Image Text:An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 4.00 mT. The angular momentum of the electron about the center of the circle is 6.00 x 10-25 1.s. (a) Determine the radius of the circular path. cm (b) Determine the speed of the electron. m/s
Expert Solution
Step 1

Given Information:-

Magnitude of the magnetic field is B=4.00 mT=4.00 mT×10-3 T1 mT=4.00×10-3 T

Angular momentum of the electron about the center of mass of the circle is L=6.00×10-25 J.s

Required:-

We need to calculate radius of the circular path and speed of the electron.

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