   Chapter 19, Problem 23P

Chapter
Section
Textbook Problem

A current I = 15 A is directed along the positive x-axis and perpendicular to a magnetic field. A magnetic force per unit length of 0.12 N/m acts on the conductor in the negative y-direction. Calculate the magnitude and direction of the magnetic field in the region through which the current passes.

(a)

To determine
The magnitude of the magnetic field in the region, through which the current passes.

Explanation

Given info: The magnitude of the current is 15A and is directed along the positive x-axis. The current is perpendicular to magnetic field. The magnetic force per unit length on the conductor is 0.12Nm-1 acting in the negative y-direction.

Explanation:

The magnitude of the magnetic force on a current carrying wire is given by,

F=BILsinθ

• B is the magnetic field
• I is the current on the wire
• L is the length of the wire
• θ is the angle between the direction of current and the magnetic field

Re-arrange for B ,

B=FILsinθ

Substitute 15A for I , 0

(b)

To determine
The direction of the magnetic field in the region, through which the current passes.

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