   Chapter 19, Problem 46P

Chapter
Section
Textbook Problem

In 1962 measurements of the magnetic field of a large tornado were made at the Geophysical Observatory in Tulsa, Oklahoma. If tile magnitude of the tornado’s field was B = 1.50 × 10−8 T pointing north when the tornado was 9.00 km east of the observatory, what current was carried up or down the funnel of the tornado? Model the vortex as a long, straight wire carrying a current.

To determine
The current that was carried up or down the funnel of the tornado.

Explanation

Given info: The magnitude of the tornados field was 1.50×108T pointing north when the tornado was 9.00km east of the observatory.

Explanation:

When the tornado is modeled as a long wire carrying current, the magnetic field will be

B=μ0I2πr

• μ0 is the permeability of free space
• I is the current
• r is the distance of the point from the straight conductor

On re-arrangement,

I=2πrBμ0

Substitute 4π×107TmA-1 for μ0 , 1.50×108T for B , 9.00km for r to determine the current,

I=2π(9

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