   # Perform each of the following conversions within the metric system: 4332 mm to m 1.76 kg to g 4619 mg to kg 0.0117 L to mL ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 2, Problem 25E
Textbook Problem
4 views

## Perform each of the following conversions within the metric system:4332 mm to m1.76 kg to g4619 mg to kg0.0117 L to mL

Interpretation Introduction

Interpretation:

Each of the given conversions within the metric system are to be performed.

Concept Introduction:

 Dimensional analysis is useful in the conversion of one unit to another.

 To convert a quantity au1 from one unit to another, that is, u1u2, first write a conversion factor, u2u1, then multiply the conversion factor with the given quantity au1 and cancel the units to get the quantity in the desired unit.

au1×u2u1=au2

### Explanation of Solution

a) 4332 mm to m

To convert mm to m, first write the correct conversion factor by using the following relationship.

1000 mm=1 m

Thus, the conversion factor is (1 m1000 mm).

Multiply the conversion factor with the given quantity, and then cancel the units to get the desired quantity.

Hence,

(4332mm)×(1 m1000mm)=4.332 m

b) 1.76 kg to g

To convert kg to g, first write the correct conversion factor by using the following relationship:

1 kg=1000 g

Thus, the conversion factor is (1000 g1 kg).

Multiply the conversion factor with the given quantity and then, cancel the units to get the desired quantity.

Hence,

(1.76 kg)×(1000 gkg)=1

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