What is your conclusion (interpretation) from frequency distribution tables and graphs for thestudents? CumulativeRelativePercent relativeClass IntervalFrequency (f)frequency (cf)frequencyfrequency150 to less than88을= 0.26726.7%156156 to less than88 + 8 = 1630= 0. 26726.7%162162 to less than316+ 3 = 1910%30168168 to less than19 + 6 = 25음 %= 0.220%174More than 174525 + 5 = 30긁= 0.16716.7%30ΣΙ-N 30 2) Scatter plot with smooth linesHeight185180WW175170165160155150145101520253035No. of studnts2) Scatter plot with smooth linesHeight185180175170165160155150145101520253035No. of studntsHeight

The very basic pattern of graphs . It is very useful in statistics.

Answered: What is your conclusion…

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Statistics

What is your conclusion (interpretation) from frequency distribution tables and graphs for the students?

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section11.1: Stem-and-leaf Plots And Histograms

Problem 5E

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Population Genetics In the study of population genetics, an important measure of inbreeding is the proportion of homozygous genotypesthat is, instances in which the two alleles carried at a particular site on an individuals chromosomes are both the same. For population in which blood-related individual mate, them is a higher than expected frequency of homozygous individuals. Examples of such populations include endangered or rare species, selectively bred breeds, and isolated populations. in general. the frequency of homozygous children from mating of blood-related parents is greater than that for children from unrelated parents Measured over a large number of generations, the proportion of heterozygous genotypesthat is, nonhomozygous genotypeschanges by a constant factor 1 from generation to generation. The factor 1 is a number between 0 and 1. If 1=0.75, for example then the proportion of heterozygous individuals in the population decreases by 25 in each generation In this case, after 10 generations, the proportion of heterozygous individuals in the population decreases by 94.37, since 0.7510=0.0563, or 5.63. In other words, 94.37 of the population is homozygous. For specific types of matings, the proportion of heterozygous genotypes can be related to that of previous generations and is found from an equation. For mating between siblings 1 can be determined as the largest value of for which 2=12+14. This equation comes from carefully accounting for the genotypes for the present generation the 2 term in terms of those previous two generations represented by for the parents generation and by the constant term of the grandparents generation. a Find both solutions to the quadratic equation above and identify which is 1 use a horizontal span of 1 to 1 in this exercise and the following exercise. b After 5 generations, what proportion of the population will be homozygous? c After 20 generations, what proportion of the population will be homozygous?
Cardiovascular DiseaseSuppose the incidence rate of myocardial infarction (MI)was 5 per 1000 among 45- to 54-year-old men in 2000.To look at changes in incidence over time, 5000 men in thisage group were followed for 1 year starting in 2010. Fifteennew cases of MI were found.Suppose that 25% of patients with MI in 2000 died within24 hours. This proportion is called the 24-hour case-fatalityrate.7.14 Of the 15 new MI cases in the preceding study,5 died within 24 hours. Test whether the 24-hour casefatality rate changed from 2000 to 2010.
Cardiovascular DiseaseSuppose the incidence rate of myocardial infarction (MI)was 5 per 1000 among 45- to 54-year-old men in 2000.To look at changes in incidence over time, 5000 men in thisage group were followed for 1 year starting in 2010. Fifteennew cases of MI were found. Suppose that 25% of patients with MI in 2000 died within24 hours. This proportion is called the 24-hour case-fatalityrate.7.14 Of the 15 new MI cases in the preceding study,5 died within 24 hours. Test whether the 24-hour casefatality rate changed from 2000 to 2010.
Cardiovascular DiseaseSuppose the incidence rate of myocardial infarction (MI) was 5 per 1000 among 45-to 54-year-old men in 2000. To look at changes in incidence over time, 5000 men in this age group were followed for 1 year starting in 2010. Fifteen new cases of MI were found. Suppose that 25% of patients with MI in 2000 died within 24 hours. This proportion is called the 24-hour case-fatality rate. 7.14 Of the 15 new MI cases in the preceding study, 5 died within 24 hours. Test whether the 24-hour casefatality rate changed from 2000 to 2010. 7.15 Suppose we eventually plan to accumulate 50 MI cases during the period 2010–2015. Assume that the 24-hour case-fatality rate is truly 20% during this period. How much power would such a study have in distinguishing between case-fatality rates in 2000 and 2010–2015 if a two-sided test with significance level .05 is planned? 7.16 How large a sample is needed in Problem 7.15 to achieve 90% power?
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Homogeneity occurs when occurs when there is not variability in a sample there is a nonlinear relationship between the X and Y scores. the variability between the populations of interest are the same occurs when there is no variability in a population
Attack rate for influenza by age andtreatment group age QIV group Control group 3-4 3.78% 5.69% 5-8 1.70% 0.15% Suppose that 80% of 3–4-year-old children and 70% of 5–8-year-old children in a village are vaccinated with QIV vaccine. Also assume that children who are not vaccinated have twice the incidence of influenza as the control group in Table. What % of 3–4-year-old children in the village will get influenza? (Hint: Use the law of total probability. P(B)=P(B|A1) x P(A1) + P(B|A2) x P(A2) ) What % of 5–8-year-old children in the village will get influenza? (Hint: Use the law of total probability. P(B)=P(B|A1) x P(A1) + P(B|A2) x P(A2) )
(A) An outbreak of certain illness was attributed to ice creams produced at a certain factory. Scientists measured the level of the illness causing factor in 10 randomly sampled batches of ice cream. The levels were: 0.583, 0.242, 0.129, 0.691, 0.231, 0.693, 0.619, 0.392, 0.418. What is the estimated interval of population mean at 0.05 level of significance? Chosse closest possible answer." 0.2809 to 0.4074 0.2709 to 0.7064 0.1289 to 0.6074 0.2809 to 0.6074 0.2109 to 0.5074 what is the correct option? (B); A population comprises of 9 people. Their IQ scores were recorded as 95, 135, 70,85,90,100,100, 110 and 115.What is the X value for a probability of 63.31% from left tail? Chosse closest possible answer. a.110.23 b.23 c.106.00 d.92.00 e.67
Salary ($) | Number of Employees 18000 - 20999 | 4 21000 - 23999 | 16 24000 - 26999 | 14 27000 - 29999 | 7 30000 - 32999 | 3 33000 - 35999 | 0 36000 - 38999 | 0 39000 - 41999 | 0 42000 - 44999 | 2 45000 - 47999 | 0 48000 - 50999 | 1 Calculate the median salary to the nearest dollar. Calculate the mean salary to the nearest dollar. Calculate the modal salary to the nearest dollar. Calculate the standard deviation of the salaries to the nearest whole number.