   Chapter 20, Problem 10P

Chapter
Section
Textbook Problem

The flexible loop in Figure P20.10 has a radius of 12 cm and is in a magnetic field of strength 0.15 T. The loop is grasped at points A and B and stretched until us area is nearly zero. If it takes 0.20 s to close the loop, what is the magnitude of the average induced cmf in it during this time? Figure P20.10Problems 10, 12 and 22.

To determine
Magnitude of average induced emf.

Explanation

Given Info: magnetic field of a loop is 0.15T, radius of the loop is 12cm and change in time is 0.20s

Formula to calculate the induced emf within the  loop is,

ε=ΔϕBΔt

• ΔϕB is the change in magnetic flux
• Δt is the change in time

The magnetic field is constant, So, the change in the area of the coil with respect to time induces the emf in the loop.

Formula to calculate the  magnetic flux is,

ϕBΔt=B(ΔAΔt)

• B is the magnetic field,
• ΔA is the change in area of the loop,

Formula to calculate the change area of the circular loop is,

ΔA=π(r22r12)

• r1 is the radius of the loop before stretching,
• r2 is the radius of the loop after stretching,

Use B(ΔA/Δt) for ΔϕB

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