Chapter 3, Problem 47AP

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a spitting cobra rears up to a height of 0.500 m above the ground and launches venom at 3.50 m/s, directed 50.0° above the horizon. Neglecting air resistance, find the horizontal distance traveled by the venom before it hits the ground.

To determine
The horizontal distance travelled by the venom before it hits the ground.

Explanation

The components of the initial velocity of the venom when v0=3.50â€‰m/s and Î¸=50.0Â° are,

v0x=v0cosÎ¸

Here,

v0 is the initial velocity

Î¸ is the angle of projection

v0x=(3.50â€‰m/s)cos50.0Â°=2.25â€‰m/s

v0y=v0sinÎ¸=(3.50â€‰m/s)sin50.0Â°=2.68â€‰m/s

The final velocity of the venom before hitting the ground is negative and is given by

vy=âˆ’voy2âˆ’2gÎ”y

Here,

vy is the vertical velocity

v0y is the vertical component of the initial velocity

g is the acceleration due to gravity

Î”y is the vertical displacement

Substitute 2.68â€‰m/s for v0y , âˆ’0.500â€‰m for Î”y and 9.80â€‰m/s2 for g .

vy=âˆ’(2

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