   Chapter 3, Problem 7CQ

Chapter
Section
Textbook Problem

Two projectiles are thrown with the same initial speed, one at an angle θ with respect to the level ground and the other at angle 90° − θ. Both projectiles strike the ground at the same distance from the projection point Are both projectiles in the air for the same length of time?

To determine
If two objects are thrown with the same initial speed and angles θ and (90°θ), they will spend the same time in the air.

Explanation

The formula for the time of flight of a projectile is,

T=2usinθg

Here,

u is the initial velocity

g is the acceleration due to gravity

θ is the angle of projection

The time of flight depends on the sine of the angle of projection and the initial velocity. If the initial velocities for two projectiles are the same, then depending on the angle of projection, the time of flight of the two projectiles can differ.

Conclusion:

If the angle of projection is θ , the time of flight is,

T=2usinθ

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