The two speakers are placed 40.0 cm apart. A single oscillator makes the speakers vibrate in phase at a frequency of 1.98 kHz. At what angles, measured from the perpendicular bisector of the line joining the speakers, would a distant observer hear maximum sound intensity? Minimum sound intensity? (Take the speed of sound to be 340 m/s. Enter the magnitude of the angle only.)maximum intensities: (List smallest magnitude angle first.)?1max = ?2max = ?3max = minimum intensities: (List smallest magnitude angle first.)?1min = ?2min = The two speakers are placed 40.0 cm apart. A single oscillator makes the speakers vibrate in phase at a frequency of 1.98 kHz. Atwhat angles, measured from the perpendicular bisector of the line joining the speakers, would a distant observer hear maximumsound intensity? Minimum sound intensity? (Take the speed of sound to be 340 m/s. Enter the magnitude of the angle only.)maximum intensities: (List smallest magnitude angle first.)0.1max0 2max03maxminimum intensities: (List smallest magnitude angle first.)01min02min

SOlution: Given that d = 40 cm f = 1.98 kHz

Answered: The two speakers are placed 40.0 cm…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter27: Wave Optics

Section: Chapter Questions

Problem 19P

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The two speakers are placed 40.0 cm apart. A single oscillator makes the speakers vibrate in phase at a frequency of 1.98 kHz. At what angles, measured from the perpendicular bisector of the line joining the speakers, would a distant observer hear maximum sound intensity? Minimum sound intensity? (Take the speed of sound to be 340 m/s. Enter the magnitude of the angle only.)
maximum intensities: (List smallest magnitude angle first.)
?1max =
?2max =
?3max =

minimum intensities: (List smallest magnitude angle first.)
?1min =
?2min =

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