Two radio antennas separated by d = 300 m, as shown in Figure P24.7, simultaneously broadcast identical signals at the same wavelength. A car travels due north along a straight line at position x = 1 000 m from the center point between the antennas, and its radio receives the signals. (a) If the car is at the position of the second maximum after that at point o when it has traveled a distance of y = 400 m northward, what is the wavelength of the signals? (b) How much farther must the car travel from this position to encounter the next minimum in reception? Hint: Do not use the small angle approximation in this problem.

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Q: n = 1.45

A: Refer attachment

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A: The equation for the transmitted intensity is

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Interference of Light

The word "constructive" signifies addition in interference. Constructive interference occurs when the path of the waves that start from the slit differs by 1 entire wavelength or in the intervals of the same. Hence, the waves that are presented on the screen are in phase (crest to crest/trough to trough). The waves interfering constructively forms bright fringes on the screen.