   Chapter 4, Problem 67P

Chapter
Section
Textbook Problem

In Figure P4.64, m1 = 10. kg and m2 = 4.0 kg. The coefficient of static friction between m1 and the horizontal surface is 0.50, and the coefficient of kinetic friction is 0.30. (a) If the system is released from rest, what will its acceleration be? (b) If the system is set in motion with m2 moving downward, what will be the acceleration of the system?

(a)

To determine
The acceleration.

Explanation

Given info: The masses are m1 = 10 kg and m2 = 4.0 kg. The co-efficient of static friction ( μs ) is 0.50 and co-efficient of kinetic friction ( μk ) is 0.30.

Explanation:

The free body diagram is given below.

The formula for static friction is,

(Fs)max=μsm1g

• m1 is the mass of the upper block.
• g is the acceleration due to gravity.

The formula for weight of the mass hanging down is,

W=m2g

• m2 is the mass of the upper block

(b)

To determine
The acceleration when m2 is moving downward.

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